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if the index is nine 125 to the power 6 ( 6 is in the radical) how would I step by step simplify ? Q. I have to use rational exponents to simplify each radical, assuming all variables are positive Asked by Gill - Sat Nov 1 14:40:52 2008 - - 1 Answers - 0 Comments A. (125^1/9)^6 = 125^6/9 = 125^2/3 = 5^2 = 25 125^1/3 = 5 Answered by Dee W - Sat Nov 1 14:45:02 2008 Using the product prop.index 4 32 m fourth power (4th power is in the radical)? Q. assuming all variables can be any real number . Can you show me step by step - thanks in advance Asked by Presly - Sat Nov 1 20:45:34 2008 - - 1 Answers - 0 Comments A. fourth root of 32 32 = 2 * 2 * 2 * 2 * 2 32^1/4 = 2(2^1/4) Answered by Dee W - Sat Nov 1 20:50:00 2008 okay heres another radical question?
Q. This is ridiculous the answers i get seem right to other people but the answer i keep getting is not on the answer key. heres another one. 8 index # 3 radical 189 + index # 3 rad 162 i keep getting the answer... 27 index # 3 rad 13 help and explanation... :] please and thank you. Asked by Char - Sat Dec 12 20:40:05 2009 - - 1 Answers - 0 Comments A. when the index is 3, it means "cube root" and you need 3 factors to be the same and come out as one. easy example: cube root of 8 = cube root of 2*2*2 = 2 now look at what you have: cube root of 189 = cube root of 3*3*3*7 = 3(cube root of 7) so, 8 times cube root of 189 = 24 cube root of 7. cube root of 162 = cube root of 3*3*3*3*2 = 3(cube root of 6) putting it all together, you get: 24 cube root 7 + 3 cube root 6 that's it! ;) Answered by Marley K - Wed Dec 16 13:10:07 2009 From Yahoo Answer Search: "radical index" What Was Karl Rove Thinking? Some Clues From His Autobiography
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