index is three 8 a cubed b to the power 12 to the power 12 ( 12 is in the radical) how would I step by step s?
Q. I have to use rational exponents to simplify each radical, assuming all variables are positive
Asked by Gill - Sat Nov 1 14:55:31 2008 - - 2 Answers - 0 Comments

A. There's no real good way to say 'cube root', so let's just understand cubrt() as your whole radical... cubrt(8 a^3 b^12) First, it's a lot easier to read if you separate the terms... = cubrt(8) * cubrt(a^3) * cubrt(b^12) Now change to rational exponents... = 8^(1/3) * a^(3/3) * b^(12/3) = 2 * a^1 * b^4 = 2ab^4
Answered by Michael W - Mon Nov 3 22:38:29 2008

Dividing radicals with same index?
Q. 3 index 3 radical 96 divided by 12 index 3 radical 4 I'm not sure what the index is, but its like an exponent next to the left of the radicand.
Asked by chopsuey - Wed Dec 5 22:00:14 2007 - - 1 Answers - 0 Comments

A. An index number on the radical is the degree of the radical. A way of remembering this is that the square root as an index number of 2. So the 3 in your equation is the third root. I figured it out and the answer is 1*cube root of 3 / 6. Cube root means it has an index number of 3.
Answered by El Pendejo! - Wed Dec 5 22:12:45 2007

Need help with Multiplying a Radical Expression?
Q. Need help solving, but would also like to understand HOW (step by step)it is solved. Any help would be greatly appreciated. Thanks in advance. Index 3 2x^3(y+z) * Index 6 2^4x^3(y+z)^35 both the 2x^3(y+z) and the 2^4x^3(y+5)^35 are entirely under the radical.
Asked by mmperry7 - Thu Apr 19 16:03:16 2007 - - 1 Answers - 0 Comments

A. [2x^3(y+z)]^(1/3) *[2^4x^3(y+z)^35 ]^(1/6) = [2^2 x^6 (y+z)^2 2^4 x^3 (y+z)^35 ]^(1/6) = [ 2^6 x^9 (y+z)^37 ]^(1/6) = 2 x^(3/2) (y+z)^(37/6)
Answered by hustolemyname - Thu Apr 19 16:20:23 2007